My Little Garden of Code

Feb 6, 2017 - 1 minute read - Comments -

Testing MathJax

\[f(x;\mu,\sigma^2) = \frac{1}{\sigma\sqrt{2\pi}}e^{-\frac{1}{2}\left(\frac{x-\mu}{\sigma}\right)^2}\]

$$ \begin{align} \mbox{Union: } & A\cup B = \{x\mid x\in A \mbox{ or } x\in B\} \\ \mbox{Concatenation: } & A\circ B = \{xy\mid x\in A \mbox{ and } y\in B\} \\ \mbox{Star: } & A^\star = \{x_1x_2\ldots x_k \mid k\geq 0 \mbox{ and each } x_i\in A\} \\ \end{align} $$

\[e^{i \pi} + 1 = 0\]

FUNemployment Migrated blog from Octopress to Hugo

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